p^2(p+2)-p(p+2)-12(p+2)=0

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Solution for p^2(p+2)-p(p+2)-12(p+2)=0 equation: 


Simplifying
p2(p + 2) + -1p(p + 2) + -12(p + 2) = 0

Reorder the terms:
p2(2 + p) + -1p(p + 2) + -12(p + 2) = 0
(2 * p2 + p * p2) + -1p(p + 2) + -12(p + 2) = 0
(2p2 + p3) + -1p(p + 2) + -12(p + 2) = 0

Reorder the terms:
2p2 + p3 + -1p(2 + p) + -12(p + 2) = 0
2p2 + p3 + (2 * -1p + p * -1p) + -12(p + 2) = 0
2p2 + p3 + (-2p + -1p2) + -12(p + 2) = 0

Reorder the terms:
2p2 + p3 + -2p + -1p2 + -12(2 + p) = 0
2p2 + p3 + -2p + -1p2 + (2 * -12 + p * -12) = 0
2p2 + p3 + -2p + -1p2 + (-24 + -12p) = 0

Reorder the terms:
-24 + -2p + -12p + 2p2 + -1p2 + p3 = 0

Combine like terms: -2p + -12p = -14p
-24 + -14p + 2p2 + -1p2 + p3 = 0

Combine like terms: 2p2 + -1p2 = 1p2
-24 + -14p + 1p2 + p3 = 0

Solving
-24 + -14p + 1p2 + p3 = 0

Solving for variable 'p'.

The solution to this equation could not be determined.

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